You are given a 0-indexed string s
of even length n
. The string consists of exactlyn / 2
opening brackets '['
and n / 2
closing brackets ']'
.
A string is called balanced if and only if:
- It is the empty string, or
- It can be written as
AB
, where bothA
andB
are balanced strings, or - It can be written as
[C]
, whereC
is a balanced string.
You may swap the brackets at any two indices any number of times.
Return the minimum number of swaps to makes
balanced.
Input: s = "][][" Output: 1 Explanation: You can make the string balanced by swapping index 0 with index 3. The resulting string is "[[]]".
Input: s = "]]][[[" Output: 2 Explanation: You can do the following to make the string balanced: - Swap index 0 with index 4. s = "[]][][". - Swap index 1 with index 5. s = "[[][]]". The resulting string is "[[][]]".
Input: s = "[]" Output: 0 Explanation: The string is already balanced.
n == s.length
2 <= n <= 106
n
is even.s[i]
is either'['
or']'
.- The number of opening brackets
'['
equalsn / 2
, and the number of closing brackets']'
equalsn / 2
.
implSolution{pubfnmin_swaps(s:String) -> i32{letmut count = 0;letmut ret = 0;for c in s.chars(){if c == '['{ count += 1;}elseif c == ']' && count > 0{ count -= 1;}else{ count += 1; ret += 1;}} ret }}